Title text:

Unstoppable force-carrying particles can’t interact with immovable matter by definition.

Transcript:

[An arrow pointing to the right and a trapezoid are labeled as ‘Unstoppable Force’ and ‘Immovable Object’ respectively.]
[The arrow is shown as entering the trapezoid from the left and the part of it in said trapezoid is coloured gray.]
[The arrow is shown as leaving the trapezoid to the right and is coloured black.]
[Caption below the panel:] I don’t see why people find this scenario to be tricky.

Source: https://xkcd.com/3084/

explainxkcd for #3084

  • Snazz@lemmy.world
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    11 hours ago

    It may be worth it to decide how we define ‘unstoppable force’ and ‘immovable object’.

    An Immovable Object has 0 velocity:

    v = 0

    Acceleration is the time derivative of velocity:

    a = d/dt(v(t))

    a = d/dt(0)

    a = 0

    And we know that

    a = Fnet / m

    An object with infinite mass would satisfy this equation, but an object with no net force would too. We could add a correction force that will satisfy the constraint of 0 net force.

    |Fnet| = 0

    ∑Fi = 0

    Fcorrection + … = 0

    To satisfy Newton’s 3rd law, we would need a reaction force to our correction force somewhere, but let’s not worry about that for now.

    A physics definition of ‘Unstoppable Force’ is:

    |Funstoppable| =/= 0

    In this case the gravitational force fits this description, given a few constraints

    Fg = Gm∑ Mi / xi2

    As long as the gravitational constant G is not 0, our object has mass, and

    ∑ Mi / xi2 =/= 0, then

    |Fg| > 0

    But this does feel kinda like cheating because it’s not really what people mean by ‘unstoppable force’. the other way to define it is just immovable object in a different reference frame.

    a = 0, |v| > 0

    I’m gonna stop here because this is annoying to type out on mobile