Paris aims to drive large sports utility vehicles (SUVs) out of its centre by hiking parking fees for heavy cars in the French capital, and it plans a citizens' vote on the proposal early next year.
Depends on what the goal is. Heavy vehicles do disproportionately more damage to the infrastructure.
They might want to encourage smaller, lighter cars, regardless of type. They certainly make small city EVs, as well as just encouraging walking, biking, public transportation, etc.
It doesn’t work like that when you have exponential damage with weight. Cars use road capacity, but damage from cars just isn’t there. You get damage from seen semi trucks, freeze thaw cycles, etc.
trucks don’t travel in certain areas in most cities so these vehicles can cause problems in hard to reach areas including inside parking structures. They also tend to limit visibility by being taller than an average person, which can make life more dangerous for pedestrians. There’s a lot of reasons to want to limit SUVs.
A small city car (Kia Picanto) weighs about 900 kg (~2000 pounds), a regular Ford Mustang weighs just under twice that, a Mustang Mach E weighs over twice that and then some.
Damage done will go up.
If you take into account the amount of people a bus transports, or the “useful work” a small semi and garbage trucks do, not even a small city car can win in terms of damage done– let alone a monster of a vehicle carrying one to two persons.
The fourth power equation you’re talking about is weight per axle. A semi truck will weigh much more in total. But the difference in weight per axle isn’t as high as you seem to think.
Depends on what the goal is. Heavy vehicles do disproportionately more damage to the infrastructure.
They might want to encourage smaller, lighter cars, regardless of type. They certainly make small city EVs, as well as just encouraging walking, biking, public transportation, etc.
Yeah but damage goes up exponentially with weight, so the problem is semi trucks, garbage trucks, buses, etc. Not cars.
Except when the amount of cars is an order or two of magnitude greater than those other two, heavy cars do take their toll on the road surface
It doesn’t work like that when you have exponential damage with weight. Cars use road capacity, but damage from cars just isn’t there. You get damage from seen semi trucks, freeze thaw cycles, etc.
So what? When there’s a lot more cars, especially within a city, and when those cars get a lot heavier, it will do a lot more damage.
A semi isn’t going to drive over inner city roads, at least not regularly.
When damage goes up to the fourth power, cars are very, very minor. While EVs are a bit heavier, they are not that much heavier.
Semi, garbage trucks, transit buses, yellow buses, moving trucks, etc are the ones that wear on roads and what roads are designed for.
I’m amazed at the downvotes.
trucks don’t travel in certain areas in most cities so these vehicles can cause problems in hard to reach areas including inside parking structures. They also tend to limit visibility by being taller than an average person, which can make life more dangerous for pedestrians. There’s a lot of reasons to want to limit SUVs.
A small city car (Kia Picanto) weighs about 900 kg (~2000 pounds), a regular Ford Mustang weighs just under twice that, a Mustang Mach E weighs over twice that and then some.
Damage done will go up.
If you take into account the amount of people a bus transports, or the “useful work” a small semi and garbage trucks do, not even a small city car can win in terms of damage done– let alone a monster of a vehicle carrying one to two persons.
Now tell me how much a fully loaded semi truck weighs.
Then take the fourth power of all three of those and compare the results.
I’ve repeated myself enough, cheers.
Literally ignoring my points kthxbye
The fourth power equation you’re talking about is weight per axle. A semi truck will weigh much more in total. But the difference in weight per axle isn’t as high as you seem to think.
It’s not exponential. https://en.wikipedia.org/wiki/Fourth_power_law?wprov=sfla1
Perhaps I should say geometric growth. In any case to the fourth power is quite high growth.
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